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https://www.zhihu.com/video/952535927516561408
Introduction
此章节我们将学习如何通过一个按钮打开或者关闭LED。

What you will need
- 树莓派×1
- 面包板×1
- 网线×1
- LED×1
- 按钮×1
- 电阻(220Ω)×1
- 杜邦线

What you will do
使用一个常开按钮作为树莓派的一个输出,当这个按钮被按下的时候,连接此按钮的GPIO(通用输入输出)将会变成低电平(0V)。通过编程,我们可以检测到连接至按钮的GPIO的状态。也就是,当这个GPIO变成低电平,那意味着按钮被按下,你可以以此为前提运行相应的代码。在这个实验中,我们会让点亮LED。

第一步:如下图所示连接电路

第二步:使用nano编辑和保存代码

Python code
#!/usr/bin/env python
import RPi.GPIO as GPIO
LedPin = 11 # pin11 --- led
BtnPin = 12 # pin12 --- button
Led_status = 1
def setup():
GPIO.setmode(GPIO.BOARD) # Numbers GPIOs by physical location
GPIO.setup(LedPin, GPIO.OUT) # Set LedPin's mode is output
GPIO.setup(BtnPin, GPIO.IN, pull_up_down=GPIO.PUD_UP) # Set BtnPin's mode is input, and pull up to high level(3.3V)
GPIO.output(LedPin, GPIO.HIGH) # Set LedPin high(+3.3V) to off led
def swLed(ev=None):
global Led_status
Led_status = not Led_status
GPIO.output(LedPin, Led_status) # switch led status(on-->off; off-->on)
if Led_status == 1:
print 'led off...'
else:
print '...led on'
def loop():
GPIO.add_event_detect(BtnPin, GPIO.FALLING, calCLEAR
lback=swLed) # wait for falling
while True:
pass # Don't do anything
def destroy():
GPIO.output(LedPin, GPIO.HIGH) # led off
GPIO.cleanup() # Release resource
if __name__ == '__main__': # Program start from here
setup()
try:
loop()
except KeyboardInterrupt: # When 'Ctrl+C' is pressed, the child program destroy() will be executed.
destroy()
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